0.5x^2+4,5x=0

Solution for 0.5x^2+4,5x=0 equation:

0.5x^2+4.5x=0

a = 0.5; b = 4.5; c = 0;
Δ = b2-4ac
Δ = 4.52-4·0.5·0
Δ = 20.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4.5)-\sqrt{20.25}}{2*0.5}=\frac{-4.5-\sqrt{20.25}}{1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4.5)+\sqrt{20.25}}{2*0.5}=\frac{-4.5+\sqrt{20.25}}{1}
$